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1. Design and Calculation of Measurement Triangle Weir
Design and Calculation of Measurement Triangle Weir: Firstly, calculate based on known conditions: sewage treatment scale of the sewage plant: $Q=5000 (m ^ 3/day) $Comprehensive coefficient of variation: $Kz=1.73 $Triangle Weir angle: $theta=90 (deg) $Calculate the maximum hourly flow rate:$ Q_{max} = dfrac{Q times K_z}{86400} = dfrac{5000 times 1.73}{86400} = 0.100(m^3/s)$ Next, design calculations will be carried out:
1. The maximum size of each part of the triangular weir is the water head on the large weir$ H_1 = {{(dfrac{Q_{max}}{1.43})}^{dfrac{2}{5}}} = {{(dfrac{0.100}{1.43})}^{dfrac{2}{5}}} = 0.35(m)$ Taking the super height of the triangular weir: $H_1 "=0.15 (m) $Triangle weir height: $H2=H_1+H_1"=0.35+0.15=0.50 (m) $Triangle weir upper mouth width: $B1=2 times H2=2 times 0.50=1.00 (m) $
2. Downstream channel taking the downstream channel width: $B3=1.2 (m) $Downstream channel flow velocity: $upsilon3=0.5 (m/s) $Downstream channel water depth:$ H_3 = dfrac{Q_{max}}{(B_3 times upsilon_3)} = dfrac{0.100}{(1.2 times 0.5)} = 0.17(m)$ Upstream channel superelevation: $H "=0.15 (m) $Downstream below the bottom point of the triangular weir: $H" "=0.1 (m) $Total channel height: $H=H1+H3+H"+H ""=0.35+0.17+0.15+0.1=0.77 (m) $Downstream channel length: $L_1=4 times B1=4 times 1.00=4.00 (m) $
III. Upstream channel width: $B2=1.2 (m) $Upstream channel water depth: $H2=H-H "=0.77-0.15=0.62 (m) $Upstream channel flow velocity:$ upsilon_1 = dfrac{Q_{max}}{(B_2 times H_2)} = dfrac{0.100}{(1.2 times 0.62)} = 0.13(m/s)$ In summary, the design calculation of the measuring triangle weir has been completed, and the dimensions and flow velocity paramet

2. Water flow calculation formula
Triangle weir (90 degrees) 1) The load of the outlet weir of the primary sedimentation tank is not greater than 2.9L/s · m, and the surface hydraulic load is 2m3/m2 · h. The overflow per unit length of the outlet weir is equal, generally 250m3/m · d (about 0.003m3/m · s). The total length of the outlet weir is (320/3600) * 103/2.9=30.7m2. The head on the weir is H1=0.1mH2O (the height from the bottom of the triangular mouth to the upstream water surface). The flow rate of each positive land triangular weir is q1=1.343 * (0.1).) 2.47=0.00455m3/s3) The number of triangular clearing weirs is n1=q/q1=160/3600/0.00455=9.77, and 10 covers are taken for excavation. (Each pond) 4) Distance between triangular weirs L1=b/n1=3/10=0.3m
3. Calculation formula for triangular weir flow
3. Outlet triangular weir (accompanying search 90 degrees) 2.47=0.00455m3/s3) The number of triangular Lixiang weirs n1=q/q1=160/3600/0.00455=9.77, take 10. (Each pool) 4) Distance between triangular weirs L1=b/n1=3/10=0.3m
4. How to choose a suitable formula for calculating water level and flow rate?
When selecting an appropriate formula for calculating water level and flow rate, the following process should be followed:
First, clarify the weir structure. Before selecting the formula, the primary task i


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